Geometry and lone pairs of electrons in $X e O F_{4}$ molecule is__________.

Square planar, 2

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Square pyramidal, 1

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Trigonal bipyramidal, 2

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Distorted octahedraon, 1

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Solution

The correct option is B Square pyramidal, 1
$X e O F_{4} = 5 + \frac{8 - 2 - 4}{2} = 5 + 1$
bond pair lone pair

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