Question

Geometry around ${}^{\prime }X{e}^{\prime }$ in $Xe{F}_6$ is:

• A. Square bipyramidal
• B. Distorted octachedral
• C. Square antiprismatic
• D. Pentagonal pyramidal

Answer 1

The correct option is B Distorted octachedral

We know,
$\text{Total number of valence electron pair around Xe =number of bond pair+Number og lone pair}$
$\text{Therefore total number of valence electron pair around Xe}=6+1=7$
$\text{Hence hybridisation is}s{p}^3{d}^3$

Thus $Xe{F}_6\left(s{p}^3{d}^3\right)$ has distorted octahedral geometry.