wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Geometry, hybridisation and magnetic moment of the ions [Ni(CN)4]2−,[MnBr4]2− and [FeF6]4− respectively are:

A
tetrahedral, square planar, octahedral :sp3,dsp2,sp3d2:5.9,0,4.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
tetrahedral, square planar, octahedral :dsp2,sp3,sp3d2:0,5.9,4.9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
square planar, tetrahedral, octahedral :dsp2,sp3,d2sp3:5.9,4.9,0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
square planar, tetrahedral, octahedral :dsp2,sp3,sp3d2:0,5.9,4.9
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D square planar, tetrahedral, octahedral :dsp2,sp3,sp3d2:0,5.9,4.9
In [Ni(CN)4]2,
Ni+2,d10,dsp2 hybridization with square planar structure & zero unpaired electron so zero magnetic moment.
In [MnBr4]2,
Mn+2,d5,sp3 hybridization with tetrahedral structure & 5 unpaired electron so 5.89 magnetic moment.
In [FeF6]4,
Fe+2,d6,sp3d2 hybridization, so octahedral geometry & 4 unpaired electron so 4.89 magnetic moment.
(As magnetic moment μ=n(n+2) , where n is no. of unpaired electron).

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Octahedral Complexes
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon