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Question

Geometry of methyl free radical is Pyramidal.

A
True
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B
False
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Solution

The correct option is B False
No. of hybrid orbital = No. of σ bonds + No. of lps

= 3 + 0 =3

So hybridisation is sp2 and geometry is planar

1411576_152261_ans_a88a786b19214b8eb90cce0e28a56cca.png

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