Geometry of reaction intermediate in $S_{N} 1$ reaction is:

tetrahedral

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planar

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triangular bipyramidal

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none of these

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Solution

The correct option is A tetrahedral
We know that $S_{N} 1$ reaction immediately forms compounds which is $s p^{3}$ hybridised and is tetrahedral.

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S_{N} 1

S_{N} 1

C H_{3} - O - C H_{2} - C l a q .^{⊖} O H - ---- \to Δ C H_{3} - O - C H_{2} - O H

S_{N} 1

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