Give a single term substitute for each of the following:
i) $6.023 \times 10^{23}$ molecules
ii) $22.4$ litres of gas at STP
iii) $1 / 12 t h$ part of the mass of one atom of carbon
iv) The half of relative molecular mass
v) Molecular mass/ atomic mass

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Solution

(i) $1$ mole= $6.02 \times 10^{23}$ molecules
(ii) $1$ mole of gas= $22.4 L$ at STP
(iii) $1$ atomic mass unit= ${\frac{1}{12}}^{t h}$ part of mass of $1$ carbon atom.
(iv) Vapour density= $\frac{1}{2} \times$ Molecular mass
(v) $1$ gram atom/ $1$ gram molecule= Molecular mass/ atomic mass .

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Give a single term substitute for each of the following:i) 6.023×1023 moleculesii) 22.4 litres of gas at STPiii) 1/12th part of the mass of one atom of carboniv) The half of relative molecular massv) Molecular mass/ atomic mass

(i) 1 mole= 6.02×1023 molecules(ii) 1 mole of gas= 22.4L at STP(iii) 1 atomic mass unit= 112th part of mass of 1 carbon atom.(iv) Vapour density= 12× Molecular mass(v) 1 gram atom/ 1 gram molecule= Molecular mass/ atomic mass .

Give a single term substitute for each of the following:
i) $6.023 \times 10^{23}$ molecules
ii) $22.4$ litres of gas at STP
iii) $1 / 12 t h$ part of the mass of one atom of carbon
iv) The half of relative molecular mass
v) Molecular mass/ atomic mass

(i) $1$ mole= $6.02 \times 10^{23}$ molecules
(ii) $1$ mole of gas= $22.4 L$ at STP
(iii) $1$ atomic mass unit= ${\frac{1}{12}}^{t h}$ part of mass of $1$ carbon atom.
(iv) Vapour density= $\frac{1}{2} \times$ Molecular mass
(v) $1$ gram atom/ $1$ gram molecule= Molecular mass/ atomic mass .