Give an algebraic expression for the pattern 1,8,27,64.........
A
n2+n
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B
n3
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C
n2+2n
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D
n3−3
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Solution
The correct option is Bn3 Each term in the pattern is cube of a number. (1)3=1, (first term; n = 1), (2)3=8, (second term; n = 2) (1)3=1, (third term; n = 3) and so on . So, the expression of the above pattern is n3 where n= 1,2,3.......