Give an algebraic expression for the pattern nbsp-1-8-27-64-n-2-nn-3n-2-2nn-3-3

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VII

Mathematics

Algebraic Expressions as Pattern

Give an algeb...

Question

Give an algebraic expression for the pattern 1,8,27,64.........

n^{2} + n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

n^{2} + 2 n

No worries! We‘ve got your back. Try BYJU‘S free classes today!

n^{3} - 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $n^{3}$
Each term in the pattern is cube of a number.
$(1)^{3} = 1$ , (first term; n = 1),
$(2)^{3} = 8$ , (second term; n = 2)
$(1)^{3} = 1$ , (third term; n = 3) and so on .
So, the expression of the above pattern is $n^{3}$ where n= 1,2,3.......

Suggest Corrections

Similar questions

Q. Give an algebraic expression for the pattern 1,8,27,64.........

Form an algebraic expression to give the number of line segments required to make the pattern given below and find the number of line segments required for $10$ houses.

1239337

Q. Observe the pattern given below:
1, 4, 9, 16, 25, ...
The algebraic expression for

n^{t h}

term of the pattern is

Q. Observe the pattern given below:
3, 9, 19, 33...
The algebraic expression for

n^{t h}

term of the pattern is .

Q. Observe the pattern given below.
2, 6, 10, 14, ...
The algebraic expression for the

n^{th}

term of the pattern is .

Join BYJU'S Learning Program

Give an algebraic expression for the pattern 1,8,27,64.........

The correct option is B n3Each term in the pattern is cube of a number. (1)3=1, (first term; n = 1), (2)3=8, (second term; n = 2) (1)3=1, (third term; n = 3) and so on . So, the expression of the above pattern is n3 where n= 1,2,3.......

The correct option is B $n^{3}$
Each term in the pattern is cube of a number.
$(1)^{3} = 1$ , (first term; n = 1),
$(2)^{3} = 8$ , (second term; n = 2)
$(1)^{3} = 1$ , (third term; n = 3) and so on .
So, the expression of the above pattern is $n^{3}$ where n= 1,2,3.......