Give an equation for reaction of conc. $H N O_{3}$ with copper.

3 C u + {4 H N O}_{3} (c o n c) \to 3 C u {({N O}_{3})}_{2} + {2 N O}_{2} + H_{2} O

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C u + {2 H N O}_{3} (c o n c) \to C u {({N O}_{3})}_{2} + {N O}_{2} + {2 H}_{2} O

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2 C u + {4 H N O}_{3} (c o n c) \to 2 C u {({N O}_{3})}_{2} + {2 N O}_{2} + {2 H}_{2} O

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C u + {4 H N O}_{3} (c o n c) \to C u {({N O}_{3})}_{2} + {2 N O}_{2} + {2 H}_{2} O

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Solution

The correct option is D $C u + {4 H N O}_{3} (c o n c) \to C u {({N O}_{3})}_{2} + {2 N O}_{2} + {2 H}_{2} O$
$C u + {4 H N O}_{3} (c o n c) \to C u {({N O}_{3})}_{2} + {2 N O}_{2} + {2 H}_{2} O$

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