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Byju's Answer
Standard IX
Mathematics
Operations on Rational and Irrational Numbers
Give an examp...
Question
Give an example of two irrational numbers, whose
sum is an irrational number.
A
2
√
5
,
3
√
5
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B
2
√
5
,
−
2
√
5
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C
2
+
√
5
,
2
−
√
5
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D
2
+
√
5
,
3
−
√
5
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Solution
The correct option is
C
2
√
5
,
3
√
5
Consider option
A
.
The number are
2
√
5
and
3
√
5
.
Their sum
=
2
√
5
+
3
√
5
=
5
√
5
, which is an irrational number.
Consider option
B
.
The number are
2
√
5
and
−
2
√
5
.
Their sum
=
2
√
5
+
(
−
2
√
5
)
=
0
, which is a rational number.
Consider option
C
.
The number are
2
+
√
5
and
2
−
√
5
.
Their sum
=
2
+
√
5
+
2
−
√
5
=
4
, which is a rational number.
Consider option
D
.
The number are
2
+
√
5
and
3
−
√
5
.
Their sum
=
2
+
√
5
+
3
−
√
5
=
5
, which is a rational number.
Therefore, option
A
is correct.
Suggest Corrections
0
Similar questions
Q.
State true or false:
There can be a pair of irrational numbers whose sum is irrational s
uch as
√
3
+
2
and
5
+
√
2
.
Q.
Fill in the blanks to complete the proof of
2
−
√
5
as an irrational number, provided
√
3
is an irrational number.
Let’s assume
2
−
√
5
be a rational number
⇒
2
−
√
5
=
a
b
,
b
≠
0
⇒
√
5
=
(i)___________ which is a (ii)_________ number.
⇒
√
5
is a rational number.
But
√
5
is an irrational number.
Hence, we have arrived at a contradiction.
∵
2
−
√
5
is an irrational number.
Q.
Fill in the blanks to complete the proof of
2
√
5
as an irrational number, provided
√
5
is an irrational number.
Let’s assume
2
√
5
be a rational number
2
√
5
=
a
b
,
b
≠
0
⇒
√
5
=
(i)___________ which is a (ii)_________ number.
⇒
√
5
is a rational number.
But
√
5
is an irrational number.
Hence, we have arrived at a contradiction.
∵
2
√
5
is an irrational number.
Q.
Prove that
√
5
is an irrational number. Hence show that
3
+
2
√
5
is also an irrational number.
Q.
5
+
√
2
3
is an irrational number.
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