Question

Give balanced equation for the action of heat on :

Lead nitrate

Answer 1

Heating of Lead Nitrate:

• Lead nitrate on heating gives Lead oxide, Nitrogen dioxide, and oxygen.
• The chemical reaction can be written as:

$\underset{\mathrm{Lead}\mathrm{Nitrate}}{\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2}\stackrel{∆}{\to }\underset{\mathrm{Lead}\mathrm{oxide}}{\mathrm{PbO}}+\underset{\mathrm{Nitrogen}\mathrm{dioxide}}{{\mathrm{NO}}_2}+\underset{\mathrm{Oxygen}}{{\mathrm{O}}_2}$

Balancing of chemical reaction:

We get an unequal number of atoms in the reactant and product part.

Atoms	Reactant	Product
Pb	1	1
N	2	1
O	6	5

Balancing the equation-

• We multiply the lead nitrate molecule by 2.
• We multiply Lead oxide by 2.
• We multiply the Nitrogen dioxide by 4.

Atoms	Reactant	Product
Pb	2	2
N	4	4
O	12	12

Hence, the balanced equation is-

$\underset{\mathrm{Lead}\mathrm{nitrate}}{2\mathrm{Pb}{\left({\mathrm{NO}}_3\right)}_2}\stackrel{∆}{\to }\underset{\mathrm{Lead}\mathrm{oxide}}{2\mathrm{PbO}}+\underset{\mathrm{Nitrogen}\mathrm{dioxide}}{4{\mathrm{NO}}_2}+\underset{\mathrm{Oxygen}}{{\mathrm{O}}_2}$