Give equations for the action of sulphuric acid on

Potassium hydrogen carbonate

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Solution

Action of sulphuric acid on potassium hydrogen carbonate $(K H C O_{3})$ gives:

$2 K H C O_{3} + H_{2} S O_{4} \to K_{2} S O_{4} + 2 H_{2} O + 2 C O_{2} ↑$

Thus, $H_{2} S O_{4}$ reacts with carbonates and bicarbonates and liberates carbon dioxide gas.

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Similar questions

Write balanced equation for potassium hydrogen carbonate and dilute sulphuric acid.

(i) With the help of equations, give an outline for the manufacture of sulphuric acid by the contact process.
(ii) What property of sulphuric acid is shown by the reaction of concentrated sulphuric acid when heated with
(a) potassium nitrate
(b) carbon?

Give balanced chemical equation for the action of Sulphuric acid on each of the following:
(a) Potassium hydrogen carbonate.
(b) Sulphur

Q. Write the balanced equation for the following reaction :

Potassium hydrogen carbonate and dilute sulphuric acid.

Q. Give equations for the action of sulphuric acid on

(ii) Sulphur

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Give equations for the action of sulphuric acid on Potassium hydrogen carbonate

Action of sulphuric acid on potassium hydrogen carbonate (KHCO3) gives: 2KHCO3+H2SO4→K2SO4+2H2O+2CO2↑ Thus, H2SO4 reacts with carbonates and bicarbonates and liberates carbon dioxide gas.

Give equations for the action of sulphuric acid on

Potassium hydrogen carbonate

Action of sulphuric acid on potassium hydrogen carbonate $(K H C O_{3})$ gives:

$2 K H C O_{3} + H_{2} S O_{4} \to K_{2} S O_{4} + 2 H_{2} O + 2 C O_{2} ↑$

Thus, $H_{2} S O_{4}$ reacts with carbonates and bicarbonates and liberates carbon dioxide gas.