Question

Give four rational numbers equivalent to the following:​
(i) $\frac{4}{9}$
(ii) $\frac{5}{-3}$

Answer 1

(i) Multiplying numerator and denominator we get,
$\frac{4\times 2}{9\times 2}=\frac{8}{18}$
$\frac{4\times 3}{9\times 3}=\frac{12}{27}$
$\frac{4\times 4}{9\times 4}=\frac{16}{36}$
$\frac{4\times 5}{9\times 5}=\frac{20}{45}$
So, the four numbers equivalent to $\frac{4}{9}$ are $\frac{8}{18}$, $\frac{12}{27}$, $\frac{16}{36}$, and $\frac{20}{45}$

(i) Multiplying numerator and denominator we get,
$\frac{5\times 2}{-3\times 2}=\frac{10}{-6}$
$\frac{5\times 3}{-3\times 3}=\frac{15}{-9}$
$\frac{5\times 4}{-3\times 4}=\frac{20}{-12}$
$\frac{5\times 5}{-3\times 5}=\frac{25}{-15}$
So, the four numbers equivalent to $\frac{5}{-3}$ are $\frac{10}{-6}$, $\frac{15}{-9}$, $\frac{20}{-12}$, and $\frac{25}{-15}$