Give $I U P A C$ name of following compound.
$C H_{3} - C H = C H - C H = C H - C \equiv C - C H_{3}$

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Solution

$1 C H_{3} - 2 C H = 3 C H - 4 C H = 5 C H - 6 C \equiv 7 C - 8 C H_{3}$

The ene functional group is preferred over yne-group if both are present at same distance from their respective terminal carbons. Here from right side of the chain yne-group is present at 2nd carbon and ene-group is also present at 2nd carbon from left side of the chain. Hence, the numbering is done from the left side.
Hence, the IUPAC name of the compound is
$O c t a - 2, 4 - d i e n e - 6 - y n e$

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