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Kolbe Electrolysis for Alkenes

Give one chem...

Question

Give one chemical test to distinguish between Aniline and benzylamine.

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Solution

Can be distinguished by their reaction with the help of ${H N O}_{2}$ . Benzylamine resees with ${H N O}_{2}$ to form unstable diazonium salt, with the evolution of
$N_{2}$ gas. $C_{6} H_{5} {C H}_{2} {N H}_{2} + {H N O}_{2} ⟶ C_{6} H_{5} {C H}_{2} + H C L + N_{2} ↑$
$C_{6} H_{5} {N H}_{2} + {H N O}_{2} ⟶ C_{6} H_{5} N_{2}^{+} {C L}^{-} + N a c l + H_{2} O$

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Kolbe Electrolysis for Alkenes

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