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Electrochemical Series

Give overall ...

Question

Give overall reaction of Daniel cell and write mathematical expression of Nernst equation for it.

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Solution

At anode, Zn is oxidised to Zn(II) ions. At cathode, Cu(II) ions are reduced to Cu. The overall reaction is :
$Z n (s) + C u^{2 +} (a q) \to Z n^{2 +} (a q) + C u (s)$
The mathematical expression of Nernst equation is $E_{c e l l} = E_{c e l l}^{o} - \frac{0.0592}{2} l o g \frac{[Z n^{2 +}]}{[C u^{2 +}]}$

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Similar questions

Q. The cell reaction in Daniel cell is

Z n (s) + C u_{(a q)}^{2 +} \to Z n_{(a q)}^{2 +} + C u_{(s)}

and Nernst equation for single electrode potential for general electrode reaction

M_{(a q)}^{n +} + n e^{-} \to M_{(s)}

E_{M^{n +} / M} = E^{o}

M^{n +} / M - \frac{2.303 R T}{n F} l o g \frac{[M]}{[M^{n +}]}

Derive Nernst equation for Daniel Cell.

Q. Write Nernst equation for Daniel cell at equilibrium condition and derive relationship between

E_{(c e l l)}^{o}

and equilibrium constant

(K_{c})

Q. Write the overall reaction taking place in Daniel Cell.

Q. The electrode potential for the Daniell cell given is

1.1

Z n (s) | Z n^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)

Write overall cell reaction and calculate the standard Gibb's energy for the reaction. [F

= 96487

Assertion: The Nernst equation gives concentration dependence of EMF of the cell.

Reason: In a Daniell cell current flows from cathode to anode.

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