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Question

Give possible expression for the length and breadth of the rectangle whose area is : 4a2+4a−3

A
(2a3)(2a+2)
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B
(2a1)(2a3)
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C
(2a+3)(2a1)
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D
None of the above
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Solution

The correct option is C (2a+3)(2a1)
Given area of rectangle = 4a2+4a3
Let length and breadth of rectangle l and b
Then area of rectangle =lb= 4a2+4a3
=(2a)2+6a2a3
=2a(2a+3)1(2a+3)
=(2a+3)(2a1)
So, length is (2a+3)
And breadth is (2a1).

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