1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Chemistry
Amines as Bases
Give reason: ...
Question
Give reason: Aniline is a weaker base than ammonia.
Open in App
Solution
Lone pair on Nitrogen in aniline are involved in resonance with the benzene ring and therefore not available for donation to that extent as in
N
H
3
.
According to Lewis theory, the species which easily loses a pair of electron is Lewis base,
Since, ammonia can lose easily electron pair while aniline cannot, thus ammonia is a stronger base than aniline.
Suggest Corrections
0
Similar questions
Q.
Assertion :p-Anisidine is weaker base than aniline. Reason:
−
O
C
H
3
group in anisidine exerts -R effect.
Q.
Benzylamine is a stronger base than aniline because:
Q.
Cyclohexylamine is stronger base than aniline because:
Q.
Assertion :
p
K
b
of aniline is more than that of methylamine. Reason: In aniline, the lone pair of electrons on the
N
atom is delocalized over the benzene ring. As a result, the electron density of nitrogen decreases. In contrast, in
C
H
3
N
H
2
(
+
I
)
effect of
C
H
3
increases the electron density on the
N
atom. Therefore, aniline is a weaker base than methylamine and hence its
p
K
b
value is higher than that of methylamine.
Q.
Assertion :Acetylene reacts with sodamide to evolve
H
2
gas. Reason: Acetylene is a weaker acid than ammonia.
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Chemical Properties
CHEMISTRY
Watch in App
Explore more
Amines as Bases
Standard XII Chemistry
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app