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Characteristics of Equilibrium Constant

Give reason: ...

Question

Give reason:
$Z n^{2 +}$ salts are white $C u^{2 +}$ salts are blue.

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Solution

$Z n^{2 +}$ salts are white as there is no unpaired $e^{-}$ present for transition, all $e^{-} s$ are paired.
$C u^{2 +}$ salts are blue in colour as it contains $4 s^{0} 3 d^{9}$ one unpaired $e^{-}$ which can undergo $d - d$ transition.

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Similar questions

Z n^{2 +}

salts are white while

C u^{2 +}

salts are coloured. Why?

Q. Give reasons for the following:
(i)

Z n^{+ 2}

salts are while but

C u^{2 +}

salts are blue in colour.
(ii) Fluorine gives only one oxide but chlorine gives a series of oxides.

Q. Give reasons Aromatic diazonium salts are more stable than aliphatic diazonium salts.

Q. When a blue coloured copper salt is heated strongly, it forms a white copper salt. The white copper salt can be reconverted into blue copper salt by adding a liquid X.
(a) Write the formula of blue copper salt.
(b) Write the formula of white copper salt.
(c) What substance is lost when blue copper salt is converted into white copper salt?
(d) Name the liquid X.

Q. (A) Account for the following:
(i)

M n

shows the highest oxidation state of +7 with oxygen but with fluorine, it shows oxidation state of +4.
(ii)

C r^{2 +}

is a strong reducing agent.
(iii)

C u^{2 +}

salts are coloured, while

Z n^{2 +}

salts are white.
(B) Complete the following equations:
(i)

2 M n O_{2} + 4 K O H + O_{2} Δ \to

C r_{2} O_{7}^{2 -} + 14 H^{+} + 6 e^{-} \to

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