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Question

Give reasons for the following:
(a) Protanation of Phenols is difficult whereas ethanol easily undergoes protonation.
(b) Boiling point of ethanol is higher than that of dimethyl ether.
(c) Anisole on reaction with HI gives phenol and CH3I as main products and not iodobenzene and CH3OH.

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Solution

(a) In phenols, the lone pair of electrons on the oxygen atom are delocalised over the benzene ring due to resonance and hence are not easily available for protonation. In contrast, in ethanol, the lone pairs on oxygen atom are localised due to the absence of resonance and hence are easily available for protonation.

(b) Ethanol has intermolecular H-bonding due to the presence of a hydrogen attached to the electron negative oxygen atom.
Consequently, a large amount of energy is required to break these hydrogen bonds. Therefore, the boiling point of ethanol is higher than that of dimethyl ether.

(c) Protonation of anisole gives methyl phenyloxonium ion,

C6H5+O|HCH3

In this ion, the bond between O and CH3 is weaker than the bond between OC6H5 which has partial double bond character.

Therefore, attack by I ion exclusively breaks the weaker the OCH3 bond forming methyl ionide and phenol.

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