Give reasons:
(i) ${B F}_{3}$ has zero dipole moment although the $B - F$ bonds are polar.
(ii) $N a C l$ is harder than $N a$ metal.

Open in App

Solution

$(i)$ Resultant dipoles cancel out each other $∴ D i p o l e m o m e n t = 0$
$(i i)$ $N a C l$ is harder than $N a$ because $N a C l$ contain ${N a}^{+}, S i z e : {N a}^{+} < N a$ , smaller the size more is hardness.

Suggest Corrections

Similar questions

$B F_{3} a n d N F_{3}$ both molecules are covalent, but $B F_{3}$ is non-polar and $N F_{3}$ is polar. Its reason is

Explain why BeH₂ molecule has a zero dipole moment although the Be–H bonds are polar.

N H_{3}

B F_{3}

C - C l

C - C l

C H_{3} - C l

S_{N} 1

If B–Cl bond has a dipole moment, explain why BCl₃ molecule has zero dipole moment.

Join BYJU'S Learning Program