Question

Give the balanced equations for the following.

Reduction of hot copper oxide to copper using ammonia gas.

Answer 1

Ammonia:

• Ammonia is a compound of nitrogen and hydrogen.
• Its molecular formula is deduced as ${\mathrm{NH}}_3$.

When Ammonia gas is passed over hot copper oxide, copper and nitrogen gas are formed. Hence, the balanced equations for the reduction of hot copper oxide to copper using ammonia gas is as follows:

$3\mathrm{CuO}\left(\mathrm{s}\right)+2{\mathrm{NH}}_3\left(\mathrm{g}\right)\to 3\mathrm{Cu}\left(\mathrm{s}\right)+{\mathrm{N}}_2\left(\mathrm{g}\right)+3{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Elements names	The number of atoms on the reactant side	The number of atoms on the product side
$\mathrm{Cu}$	$3$	$3$
$\mathrm{O}$	$3$	$3$
$\mathrm{H}$	$6$	$6$
$\mathrm{N}$	$2$	$2$