Give the decreasing order of basic strength of the following:
a. $N H_{3}$
b. $N H_{2} O H$
c. $N H_{2} - N H_{2}$

c > b > a

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a > b > c

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c > a > b

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a > c > b

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Solution

The correct option is C $c > a > b$
The decreasing order of basic strength is $c > a > b$ or $N H_{2} - N H_{2} > N H_{3} > N H_{2} O H$ .
$N H_{2} - N H_{2}$ is most basic as it has two lone pairs of electrons.
The basic strength of ammonia is lower than the basic strength of hydrazine as ammonia contains only one lone pair.
Hydroxyl amine is least basic due to $- I$ effect of $- O H$ group which decreases the ease with which lone pair of an electron can be donated.

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