Give the decreasing order of Ka value of the following compounds.
A
(I)>(IV)>(III)>(II)
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B
(II)>(III)>(IV)>(I)
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C
(I)>(III)>(II)>(IV)
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D
(I)>(IV)>(II)>(III)
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Solution
The correct option is A(I)>(IV)>(III)>(II) Therefore, the order of acidic character, Aromatic>Non−aromatic>Anti−aromatic But anti-aromacity of (III) is more than (II) since (III) is more resonance stabilised than (II) Therefore, the order of decreasing acidic character or Ka value is (I)>(IV)>(III)>(II)