Give the decreasing order of reactivity of the following alkyl halides in the Williamson’s reaction. i.(CH3)3C−CH2Br ii.ClCH2CH=CH2 iii.ClCH2CH2CH3 iv.BrCH2CH2CH3
A
ii>iv>iii>i
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B
ii>iii>iv>i
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C
i>iii>iv>ii
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D
i>iv>iii>ii
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Solution
The correct option is Aii>iv>iii>i In Williamson's reaction, their is attack of alcohol on alkyl halide via SN2. Steric hinderance decrease the rate of SN2 and electron withdrawing groups and good leaving group increase the rate of SN2.