Give the decreasing order of reactivity of the following compounds with HBr.

I I I > I V > I I > I .

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I I I > I I > I V > I .

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I I I > I I > I > I V .

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I I > I I I > I V > I .

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Solution

The correct option is D $I I I > I I > I > I V .$
The decreasing order of reactivity with HBr is as shown. When electron donating groups such as methoxy group or methyl group are present in para position, the reactivity is high. When electron releasing groups are absent or if they are present in meta position, the reactivity is low.

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