Question

Give the decreasing order of $S_{N}1$ reactions of the following compounds in $H_{2}O$.

(i) $(C{H}_3{)}_{2}CHC{H}_{2}Br$ (ii) $C{H}_{3}CHBrC{H}_3$ (iii) $C{H}_{3}Br$

• A. (i) > (ii) > (iii)
• B. (ii) > (i) > (iii)
• C. (iii) > (ii) > (ii)
• D. (iii) > (i) > (ii)

Answer 1

Answer: (B)

(ii) > (i) > (iii)

The order of reactivity towards $S_{N}1$-
(ii)> (iii)> (i)

$\because$ Reactivity order towards $S_{N}1$: $3^o>2^o>1^o$ carbon