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B
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C
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D
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Solution
The correct options are A B C D Let us start with protonating the OH group and the water molecule departs, leaving behind a secondary carbocation. Before we step to the rearrangement part, let us find out what products are formed:
It has two locales from where a proton could be abstracted. The products formed are:
Now, the carbocation would rather rearrange into a more stable, tertiary carbocation. The tertiary carbocation gives: