Give the electronic configuration of the following complexes on the basis of crystal field splitting theory. $[C o F_{6}]^{3 -}, [F e (C N)_{6}]^{4 -}$ and $[C u (N H_{3})_{6}]^{2 +} .$

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Solution

According to spectrochemical series, ligands can be arranged in a series in the order of increasing field strength i.e., $F^{-} < N H_{3} < C N^{-} .$
Hence, $C N^{-}$ and $N H_{3}$ being strong field ligand pair up the $t_{2 g}$ electrons before filling $e_{g}$ set.
$[C o F_{6}]^{3 -}; C o^{3 +} = (d^{6}) {t_{2 g}}^{4} {e_{g}}^{2}$

$[F e (C N)_{6}^{4 -}], F e^{2 +} = (d^{6}) t_{2 g}^{6} e_{g}^{0}$

$[C u (N H_{3})_{6}]^{2 +}, C u^{2 +} = (d^{9}) t_{3 g}^{6} e_{g}^{3}$

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Give the electronic configuration of the following complexes on the basis of crystal field splitting theory. [CoF6]3−,[Fe(CN)6]4− and [Cu(NH3)6]2+.

Give the electronic configuration of the following complexes on the basis of crystal field splitting theory. $[C o F_{6}]^{3 -}, [F e (C N)_{6}]^{4 -}$ and $[C u (N H_{3})_{6}]^{2 +} .$