Question

Give the empirical formula of ${\mathrm{C}}_6{\mathrm{H}}_6$, ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$, ${\mathrm{C}}_2{\mathrm{H}}_2$, ${\mathrm{CH}}_3{\mathrm{COOH}}_{}$.

Answer 1

Step-I Empirical formula :

The simplest whole number ratio of atoms of different elements present in a compound is called an empirical formula.

Step-II

So, Empirical formula of ${\mathrm{C}}_6{\mathrm{H}}_6$(Benzene) is $\mathrm{CH}$. Because ratio of carbon atoms to hydrogen atoms in Benzene (${\mathrm{C}}_6{\mathrm{H}}_6$) is 1:1.

Step-III

Empirical formula of Glucose(${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$) is ${\mathrm{CH}}_2\mathrm{O}$. Because ratio of carbon atoms to hydrogen atoms to oxygen atoms in ${\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6$ is 1:2:1.

Step-IV

Empirical formula of ${\mathrm{C}}_2{\mathrm{H}}_2$(Acetylene) is CH. Because ratio of carbon atoms to hydrogen atoms is 1:1.

Step-V

Empirical formula of ${\mathrm{CH}}_3{\mathrm{COOH}}_{}$(Acetic acid) is ${\mathrm{CH}}_2\mathrm{O}$.Because ratio of carbon atoms to hydrogen atoms to oxygen atoms in ${\mathrm{CH}}_3\mathrm{COOH}$ is 1:2:1.