Give the formulae for the time of flight, maximum height reached and range for a projectile motion.

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Solution

Time of flight, $t = \frac{2 v_{0} s i n θ}{g}$
Maximum height reached, $H = \frac{v_{0}^{2} s i n^{2} θ}{2 g}$
Horizontal range, $R = \frac{v_{0}^{2} s i n 2 θ}{g}$

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Give the formulae for the time of flight, maximum height reached and range for a projectile motion.

Time of flight, t=2v0sinθg Maximum height reached, H=v20sin2θ2g Horizontal range, R=v20sin2θg

Time of flight, $t = \frac{2 v_{0} s i n θ}{g}$
Maximum height reached, $H = \frac{v_{0}^{2} s i n^{2} θ}{2 g}$
Horizontal range, $R = \frac{v_{0}^{2} s i n 2 θ}{g}$