Give the IUPAC name for the following alcohols. Classify as primary or secondary or teritiary alcohol.
$C H_{2} = C H - C H_{2} - C H_{2} - O H$

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Solution

$C H_{2} = C H - C H_{2} - C H_{2} - O H$
In the given compound the $- O H$ group is attached to the primary carbon atom. Thus, it is a primary alcohol.
In the given compound the parent chain consists of 4 carbon atom and there is a double bond between carbon number 3 and 4.
Thus, The IUPAC name for this alcohol is $3 - b u t e n - 1 - o l$ .

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