Give the number of neutrons in an atom of the isotope $_{47}^{107} A g$ .

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Solution

The correct option is D 60
Number of neutrons in an atom = Atomic mass (A) - Atomic Number (Z)
For $_{47}^{107} A g$
Atomic mass (A) = 107
Atomic number (Z) = 47
Thus, number of neutrons are: 107 - 47 = 60

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