Give the product of following metal displacement reaction.
$Z n + C u S O_{4} (a q) \to$

Z n (a q) + C u S O_{4} (s)

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Z n S O_{4} (a q) + C u (s)

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Z n S O_{4} (a q) + C u O (s)

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Z n S (a q) + C u (s)

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Solution

The correct option is B $Z n S O_{4} (a q) + C u (s)$
In the above reaction, zinc is a reactive metal that displaces less reactive copper from its salt solution and zinc sulphate is formed.

$Z n (s) + C u S O_{4} (a q) \to Z n S O_{4} (a q) + C u (s)$

Suggest Corrections

Similar questions

Z n_{(} s) + C u S O_{4} (a q) \to Z n S O_{4} (a q) + C u_{(} s)

C u S O_{4 (a q)} + Z n_{(s)} \to Z n S O_{4 (a q)} + C u_{(s)}

+ 2 + 6 - 2 C u S O_{4 (a q)} + 0 Z n_{(s)} \to 0 C u_{(s)} + + 2 + 6 + - 2 Z n S O_{4 (a q)}

(a) Z n_{(s)} + C u S o_{4 (a q)} \to Z n S O_{4 (a q)} + C u_{(s)}

(b) F e_{(s)} + Z n S O_{4 (a q)} \to F e S O_{4 (a q)} + Z n_{(s)}

(c) Z n_{(s)} + F e S O_{4 (a q)} \to Z n S O_{4 (a q)} + F e_{(s)}

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