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SN1 Reaction Mechanism

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Question

Give the products formed from the reactions of each of the following compounds with Hex -3-yne:
(i) $K M n O_{4}$ in warm acid
(ii) $O_{3} / H_{2} O$

Propanoic Acid

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Hex - 3 - ynoic Acid

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Hexane 3,4 dione

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Hexane 3,4 diol

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Solution

The correct option is A Propanoic Acid
Hex-3-yne reacts with $K M n O_{4}$ in warm acid and $O_{3} / H_{2} O$ to form propanoic acid.

$C H_{3} C H_{2} C \equiv C C H_{2} C H_{3} + K M n O_{4} O_{3} / H_{2} O - ---- \to 2 C H_{3} C H_{2} C O O H$
Hex-3-yne Propanoic acid
So the answer is A.

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Similar questions

K M n O_{4}

O_{3} / H_{2} O

O_{3} / H_{2} O

^{'} X^{'} (C_{2} H_{4} O)

^{'} Y^{'} (C_{2} H_{4} O_{2}) .^{'} X^{'}

H C N^{'} X^{'}

^{'} Z

2 -

^{'} X^{'}

d i l . N a O H

C H_{2} = C H C H_{2} C \equiv C H_{3} Z n - H_{2} O

^{'} X^{'} (C_{2} H_{4} O)

^{'} Y^{'} (C_{2} H_{4} O_{2}) .^{'} X^{'}

H C N^{'} X^{'}

^{'} Z

2 -

^{'} X^{'}

^{'} Y

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