You visited us 1 times! Enjoying our articles? Unlock Full Access!

SN1 Reaction Mechanism

Give the prod...

Question

Give the products formed from the reactions of each of the following compounds with Hex -3-yne:
(i) $K M n O_{4}$ in warm acid
(ii) $O_{3} / H_{2} O$

Propanoic Acid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Hex - 3 - ynoic Acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Hexane 3,4 dione

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Hexane 3,4 diol

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Propanoic Acid
Hex-3-yne reacts with $K M n O_{4}$ in warm acid and $O_{3} / H_{2} O$ to form propanoic acid.

$C H_{3} C H_{2} C \equiv C C H_{2} C H_{3} + K M n O_{4} O_{3} / H_{2} O - ---- \to 2 C H_{3} C H_{2} C O O H$
Hex-3-yne Propanoic acid
So the answer is A.

Suggest Corrections

Similar questions

K M n O_{4}

O_{3} / H_{2} O

O_{3} / H_{2} O

^{'} X^{'} (C_{2} H_{4} O)

^{'} Y^{'} (C_{2} H_{4} O_{2}) .^{'} X^{'}

H C N^{'} X^{'}

^{'} Z

2 -

^{'} X^{'}

d i l . N a O H

C H_{2} = C H C H_{2} C \equiv C H_{3} Z n - H_{2} O

^{'} X^{'} (C_{2} H_{4} O)

^{'} Y^{'} (C_{2} H_{4} O_{2}) .^{'} X^{'}

H C N^{'} X^{'}

^{'} Z

2 -

^{'} X^{'}

^{'} Y

Join BYJU'S Learning Program