Give the structures of (A), (B), and (C) in the following reaction: CH3CH2INaCN−−−−→(A)⊝OH→PartialHydrolysis(B)NaOH+Br2→(C)
Open in App
Solution
In presence of NaCN, iodoethane forms propane nitrile, which on partial hydrolysis gives ethanamide.
Amide is converted into amine with one less number of carbon atom from amide by Hofmann bromamide reaction. So, ethanamide is converted to methanamine.