Question

Give the value of quantum numbers for the electron with the highest energy in sodium atom.

• A. $n=3,l=1,m=0,s=\frac{+1}{2}$
• B. $n=3,l=0,m=0,s=\frac{+1}{2}$
• C. $n=3,l=1,m=1,s=\frac{+1}{2}$
• D. $n=3,l=1,m=-1,s=\frac{+1}{2}$

Answer 1

The correct option is B $n=3,l=0,m=0,s=\frac{+1}{2}$

For sodium, Na =${15}^2{25}^{2}2p^2{35}^1$

for highest energy n+l should be highest

so, $n=3,l=0,m=0,5=+1/2$ (of valance $e^{-})$

$henceAns-B$