Give zeroes of the polynomial p(x)=(x-1)(x-2)(x-3)(x-4)

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Solution

Given that p(x)=(x-1)(x-2)(x-3)(x-4)
if any one term in p(x) is zero
then value of p(x)=0
so if
x=1 or x=2 or x=3 or x=4
p(x)=0
so the zeros are
1,2,3,4

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Similar questions

p (x) = (x - 1) (x - 2) (x - 3)

Verify whether the following are zeroes of the polynomial, indicated against them.
(i) p(x)=3x+1,x= $\frac{- 1}{3}$

(ii) p(x)=5x− $π$ ,x= $\frac{4}{5}$

(iii) p(x)= $x^{2}$ -1,x=1,−1

(iv) p(x)=(x+1)(x−2),x=−1,2

(v) p(x)= $x^{2}$ ,x=0

Verify whether the following are zeroes of the polynomial, indicated against them.

(i) (ii)

(iii) p(x) = x² − 1, x = 1, − 1 (iv) p(x) = (x + 1) (x − 2), x = − 1, 2

(v) p(x) = x², x = 0 (vi) p(x) = lx + m

(vii) (viii)

P (x) = (x + 2) (x - 1)

- \frac{1}{2}

\frac{2}{5}

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