Given 2-3- -7-3 - - 1m Value of m is

#160; #160; 2^ 3× ( 7)^ 3 =12^3×1( 7)^3 = 18×1343 = 12744 ...

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Laws of Exponents for Real Numbers

Given 2-3× ...

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Given $2^{- 3} \times (- 7)^{- 3}$ = $- \frac{1}{m}$ Value of $m$ is

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If ${⎡ ⎣ {{(\frac{1}{7^{2}})}^{- 2}}^{- \frac{1}{3}} ⎤ ⎦}^{\frac{1}{4}} = 7^{m}$ then find the value of m.

If $m = 2$ , find the value of $3 m^{2} - 2 m - 7$ .

If $x = \frac{2}{3}$ is a solution of the quadratic equation $7 x^{2} + m x - 3 = 0$ , find the value of m.

3 m^{3} + 7 m

\frac{- 3}{2} + m - \sqrt{3} m^{3}

\frac{- 2}{3} m^{3} - 5 m^{2} + 7 m - 1

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