Given 3+a3<5+a4 ; where aϵw, a can take the value of 24.
True
False
3+a3<5+a4a3−a4<5−34a−3a12<2a<24
Given 3+a3<5+a4 ; where aϵW; a can be taken the value of 24.
Substituting x=−3 in x2+5x gives 32+5(−3)=−9−15=−24.
The value of the expression x2−5x+4 when x=−3 is, (−3)2−5×−3+4=9+15+4=28
If a+b=√5 and a−b=√3, then the value of a2+b2 is equal to 4.
In the given inequation 4y ≥ 16 ; the value of y can be equal to 4 .