Question

Given : $4\cot A=3$, then

$\sec A$ is $\frac{5}{m}$, where m is

Answer 1

$4\cot A=3$
$\cot A=\frac{3}{4}=\frac{B}{P}$
$P=4$, $B=3$
Now, $H^2=P^2+B^2$
$H^2=3^2+4^2$
$H^2=5^2$
$H=5$
$\sec A=\frac{H}{B}=\frac{5}{3}=1\frac{2}{3}$