Given A - B 2-9- c - then C is equal toA- 9-A-B2B- 81-A-B22C- 3-A-B22D- 3-A-B22

The correct option is C A B^2 = √(9/c)⇒9/c = ( A B^2)^2⇒ C = 9/( A B^2)^2 = ( 3/A B^2)^2 ...

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Expansion of (x-y)^2

Given A = B 2...

Question

Given $A = B^{2} + \sqrt{\frac{9}{c}}$ , then C is equal to

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Given $A = B^{2} + \sqrt{\frac{9}{c}}$ , then C is equal to

(a_{1}, b_{1}) a n d (a_{2}, b_{2}) i s (a_{1} - a_{2}) x + (b_{1} - b_{2}) y + c = 0

| A | = - 1, | B | = 3

| 3 A B |

$a^{2} - b^{2}$ is equal to
$(a) (a - b)^{2}$
$(b) (a - b) (a - b)$
$(c) (a - b) (a + b)$
$(d) (a + b) (a + b)$

I f x + i y = \sqrt{\frac{a + i b}{c + i d}}, t h e n (x^{2} + y^{2})^{2}

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