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Question

Given A+B=a,A×B=b,Aa=1 Find the vector B.

A
(b×a)+b(a21)a2
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B
(b×a)+b(a21)b2
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C
(b×a)+a(a21)a2
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D
(b×a)+a(a21)b2
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Solution

The correct option is D (b×a)+a(a21)a2
Given
A+B=a-------(1)
A×B=b------(2)
Aa=1------(3)
cross product w.r to B
A×B+B×B=a×B
b=a×B from eq (2)
cross product w.r to a
b×a=(a×B)×a
b×a=(aa)B(aB)a
b×a+(aB)a=a2B
putting value of B from eq (1)
b×a+(a(aA))a=a2B
b×a+(a2Aa)a=a2B
b×a+(a21)a=a2B
a2B=b×a+a(a21)
B=b×a+a(a21)a2



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