CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Given A+B=a,A×B=b,Aa=1 Find the vector B.

A
(b×a)+b(a21)a2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
(b×a)+b(a21)b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(b×a)+a(a21)a2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
(b×a)+a(a21)b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D (b×a)+a(a21)a2
Given
A+B=a-------(1)
A×B=b------(2)
Aa=1------(3)
cross product w.r to B
A×B+B×B=a×B
b=a×B from eq (2)
cross product w.r to a
b×a=(a×B)×a
b×a=(aa)B(aB)a
b×a+(aB)a=a2B
putting value of B from eq (1)
b×a+(a(aA))a=a2B
b×a+(a2Aa)a=a2B
b×a+(a21)a=a2B
a2B=b×a+a(a21)
B=b×a+a(a21)a2



flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Term
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon