Question

Given A -B-C the co-ordinate of point A is the smallest.If d(A,B) = 7.5, d(B,C):= 13,8 and the coordinate of point B is 8.5, then find the coordinates of points A and C

• A. A $\leftrightarrow$ 0, C $\leftrightarrow$ 63.2
• B. A $\leftrightarrow$ 5, C $\leftrightarrow$ 40
• C. A $\leftrightarrow$ 1, C $\leftrightarrow$ 22.3
• D. A $\leftrightarrow$ 3, C $\leftrightarrow$ 18

Answer 1

Answer: (C)

A $\leftrightarrow$ 1, C $\leftrightarrow$ 22.3

Given A -B-C the co-ordinate of point A is the smallest.If d(A,B) = 7.5, d(B,C):= 13,8 and the co-ordinate of point B is 8.5.
So,
d(AB) = co-ordinate of point B - co-ordinate of point A
=> 7.5 = 8.5 - co-ordinate of point A
=> co-ordinate of point A = 1
d(B,C) = co-ordinate of point B - co-ordinate of point C or co-ordinate of point C - co-ordinate of point B
But , If the co-ordinate of point B > co-ordinate of point C, the point C is behind the point A, then co-ordinate A is not the smallest. then,
d(B,C) = co-ordinate of point C - co-ordinate of point B
=> 13.8 = co-ordinate of point C - 8.5
=> co-ordinate of point C = 13.8 + 8.5 = 22.3