Given A=[2−620],B=[−3240],C=[4002]. Find the matrix X such that A+2X=2B+C.
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Solution
Given: A=[2−620],B=[−3240] and C=[4002] ∵A+2X=2B+C Putting the given values, we get [2−620]+2X=2[−3240]+[4002] 2X=[−6+44+08+00+2]−[2−620] X=12[−41062] X=[−2531].