Question

Given $A=\left[\begin{array}{cc}2& 1\\ 3& 0\end{array}\right],B=\left[\begin{array}{cc}1& 1\\ 5& 2\end{array}\right]andC=\left[\begin{array}{cc}-3& -1\\ 0& 0\end{array}\right]$
$2A-3B+C$

Answer 1

$=2\left[\begin{array}{cc}2& 1\\ 3& 0\end{array}\right]-3\left[\begin{array}{cc}1& 1\\ 5& 2\end{array}\right]+\left[\begin{array}{cc}-3& -1\\ 0& 0\end{array}\right]$

$=\left[\begin{array}{cc}4& 2\\ 6& 0\end{array}\right]-\left[\begin{array}{cc}3& 3\\ 15& 6\end{array}\right]+\left[\begin{array}{cc}-3& -1\\ 0& 0\end{array}\right]$

$=\left[\begin{array}{cc}4-3-3& 2-3-1\\ 6-15+0& 0-6+0\end{array}\right]$

$=\left[\begin{array}{cc}-2& -2\\ -9& -6\end{array}\right]$