Given A- 3 -2- -1 4 - B- 6- 1 - C- -4- 5 - and D- 2- 2 -Find AB-2C-4D

AB=( 3 amp; 2 1 amp; 4)( 6 1)=( 16 2) ; 2c=( 8 10) ; 4D=( 8 8) AB+2C 4D=( 0 0) . ...

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Byju's Answer

Standard XII

Mathematics

Adjoint of a Matrix

Given A=[ 3...

Question

Given $A = (\begin{matrix} 3 & - 2 - 1 & 4 \end{matrix}) B = (\begin{matrix} 61 \end{matrix}) C = (\begin{matrix} - 4 5 \end{matrix})$ and $D = (\begin{matrix} 22 \end{matrix})$ .
Find $A B + 2 C - 4 D$

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Solution

$A B = (\begin{matrix} 3 & - 2 - 1 & 4 \end{matrix}) (\begin{matrix} 61 \end{matrix}) = (\begin{matrix} 16 - 2 \end{matrix})$ ; $2 c = (\begin{matrix} - 8 10 \end{matrix})$ ; $- 4 D = (\begin{matrix} - 8 - 8 \end{matrix})$
$A B + 2 C - 4 D = (\begin{matrix} 00 \end{matrix})$ .

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Given A=(3−2−14) B=(61) C=(−45) and D=(22).Find AB+2C−4D

AB=(3−2−14)(61)=(16−2); 2c=(−810); −4D=(−8−8)AB+2C−4D=(00).

Given $A = (\begin{matrix} 3 & - 2 - 1 & 4 \end{matrix}) B = (\begin{matrix} 61 \end{matrix}) C = (\begin{matrix} - 4 5 \end{matrix})$ and $D = (\begin{matrix} 22 \end{matrix})$ .
Find $A B + 2 C - 4 D$

$A B = (\begin{matrix} 3 & - 2 - 1 & 4 \end{matrix}) (\begin{matrix} 61 \end{matrix}) = (\begin{matrix} 16 - 2 \end{matrix})$ ; $2 c = (\begin{matrix} - 8 10 \end{matrix})$ ; $- 4 D = (\begin{matrix} - 8 - 8 \end{matrix})$
$A B + 2 C - 4 D = (\begin{matrix} 00 \end{matrix})$ .