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Definition of Functions

Given a funct...

Question

Given a function $f (x) = \frac{1}{(x + 1)!}$ , the smallest integer $x$ such that $f (x) < 0.000005$ is:

A

7

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B

8

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C

9

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D

10

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E

11

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Solution

The correct option is B $8$
$f (x) = \frac{1}{(x + 1)!} < 0.000005$ , which gives $(x + 1)! > 200000$
For $x \geq 8$ , the equation holds true.
Therefore the least value of $x$ is $8$ .

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