Question

Given a number of capacitors labelled as (8$\mu$F , 250V). Find the minimum number of capacitors needed to get an arrangement equivalent to (16$\mu$F,1000V) :

• A. 4
• B. 16
• C. 32
• D. 64

Answer 1

Answer: (C)

32

Increasing voltage from 250V to 1000V requires arranging 4 capacitors in series but this decreases the $C_{net}=8/4\mu F=2\mu F$
Increasing the capacitance to $16\mu F$ requires 8 such rows placed in parallel.
Total number of capacitors $=8\times 4=32$.